Example to show ArraylistException in
Java

Here we are describing the use of using exception class
in java .This tutorial describes how to handle Array list exceptions
appropriately in your programs and designs. The steps involved in the program
are described below:-
ArraylistException.java
import java.util.*;
public class ArraylistException {
void buildAlphabet() {
ArrayList list = new ArrayList();
for (int i =1; i <=5; i++)
{
list.add(i,(String)("Girish"));
}
System.out.print("Elements of array are: " + list);
}
public static void main(String[] args) {
ArraylistException ale=new ArraylistException();
ale.buildAlphabet();
}
}
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Output of the program
Exception in thread "main" java.lang.IndexOutOfBoundsException: Index: 1, Size: 0
at java.util.ArrayList.add(ArrayList.java:367)
at ArraylistException.buildAlphabet(ArraylistException.java:11)
at ArraylistException.main(ArraylistException.java:18)
Java Result: 1 |
To avoid this error you have to give proper index for
the List means to say starting index which is 0 for the array not 1.
Download SourceCode

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