Example to show double exception in java
The Tutorial describe you a code from double exception
in java. The given below program tells about the occurrence of double exception. Double
is a class that wraps a value of the primitive type double in an object. Double
exception occurs in java when the string or primitive data type are not
converted into a double value. The step involved in a program are described
below -
1)We have a class Double Exception, that include a main
method. The main method include -
Buffered Reader- This read the text from the
character stream
read line ( ) - This is used to read a line of
text.
to string( ) - This object return you a
string irrespective of any type of data type.
In case a user try to enter a string or primitive data type, that
is not converted into a double, this causes the try block to cause exception in
a code The exception subsequently handled by a catch block and show you a user
defined message in the println.
Doubleexception.java
import java.lang.Math.*;
public class Doubleexception {
public static void main(String args[]) {
double c = 0;
try {
Double d = (500 / 100.9) ;
c = d.intValue();
} catch (Exception e) {
System.out.println(e.getMessage());
}
System.out.println("Value of c is: "+c);
}
}
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Output of the program
Note:-if you will pass any number other than
double type program will generate exception.
Download sourcr code
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