Checking whether a year is leap or not

This tutorial is going to teach you the coding for checking whether a year is a leap year or not.

This tutorial is going to teach you the coding for checking whether a year is a leap year or not. Here, we have taken the year 2000. So define an integer n=2000 in the class "Leapyear" and now apply "if else" condition. As we know leap year is divided by the integer 4 and so applying if condition as n/4=0, then "n" is a leap year. Now in the System.out.println write the message that the year is a leap year. Again applying "else" condition the output will be that the year is not a leap year.

Here is the code of program:


class  Leapyear

{

  public static void main(String[] args) 

  {

  int n=2000;

  if (n%4==0){

  System.out.println("The given year is a leap year");

  }

  else{

  System.out.println("This is not a leap year");

  }

}

}

Download the program:

Checking whether a year is leap or not

Checking whether a year is leap or not

Checking whether a year is leap or not

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