Hibernate Disjunction
This section contains explanation of Hibernate disjunction with example.
Hibernate Criteria Disjunction :
Hibernate provides Criteria disjunction which functionality is as logical OR
operator.
disjunction() groups the expressions into single expression. It returns result
if any one condition of them is satisfied.
If all the conditions are not satisfied then only it will return false.
Example : student is our table and we are going to display records of such student whose roll_no is 4 or whose name starts with 'R' character.
package net.roseindia.main;
import java.util.ArrayList;
import java.util.Iterator;
import java.util.List;
import java.util.Map;
import net.roseindia.table.Student;
import net.roseindia.util.HibernateUtil;
import org.hibernate.Criteria;
import org.hibernate.HibernateException;
import org.hibernate.Query;
import org.hibernate.Session;
import org.hibernate.Transaction;
import org.hibernate.criterion.Restrictions;
public class MainClazz {
public static void main(String[] args) {
Session session = HibernateUtil.getSessionFactory().openSession();
Criteria criteria = session.createCriteria(Student.class);
criteria.add(Restrictions.disjunction().add(Restrictions.eq("id", 4))
.add(Restrictions.like("name", "R%")));
List<Student> stud = new ArrayList<Student>();
stud = criteria.list();
Iterator iterator = stud.iterator();
System.out.println("RollNo.\tName \t Course");
while (iterator.hasNext()) {
Student student = (Student) iterator.next();
System.out.print(student.getRoll());
System.out.print("\t" + student.getName());
System.out.print("\t" + student.getCourse());
System.out.println();
}
session.close(); // session is closed
}
}
Output :
Hibernate: select this_.roll_no as roll1_0_0_, this_.course as course0_0_, this_.name as name0_0_ from student this_ where (this_.roll_no=? or this_.name like ?) RollNo. Name Course 1 Ron java 3 Roxi unix 4 Jenson Hibernate