random numbers
Hello i need this code to be modified for me to display the random numbers, but not twice or more. I mean i need a number to be display once. This code allows some numbers to be displayed more than once.
Hi Friend,
Try the following code:
import java.util.*;
class RandomNumberExample {
static Random generator = new Random();
public static int get (int[] array) {
int rnd = generator.nextInt(array.length);
return array[rnd];
}
public static void main(String[]args){
int arr[]=new int[10];
Scanner input=new Scanner(System.in);
System.out.println("Enter 10 numbers: ");
for(int i=0;i<10;i++){
arr[i]=input.nextInt();
}
System.out.println();
System.out.println("Random numbers are: ");
int random[]=new int[5];
for(int i=0;i<random.length;i++){
random[i] = RandomNumberExample.get(arr);
System.out.println(random[i]);
}
}
}
Thanks
View Answers
June 30, 2010 at 4:17 PM
Hi Friend,
Try the following code:
import java.util.*;
public class RandomNumberExample {
public static List<Integer> get(List<Integer> numbers, int noOfRandomNumbers) {
List<Integer> list = new ArrayList<Integer>(numbers);
List<Integer> randomList = new ArrayList<Integer>();
Random rd= new Random();
for (int i=0; i < noOfRandomNumbers; i++) {
int index = (int) (rd.nextDouble()*list.size());
randomList.add(list.get(index));
list.remove(index);
}
return randomList;
}
public static void main(String[] args) {
int arr[]=new int[10];
Integer in[] = new Integer[10];
Scanner input=new Scanner(System.in);
System.out.println("Enter 10 numbers: ");
for(int i=0;i<arr.length;i++){
arr[i]=input.nextInt();
in[i]=new Integer(arr[i]);
}
List<Integer> randomList = get(Arrays.asList(in),5);
for (Integer randomNumber : randomList) {
System.out.print(randomNumber + " ");
}
}
}
Thanks
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