Array copy
Hello all.could someone telle me how to copy an array (holding random numbers)
to a new array...( then make randomnumbers on this new array ) but without changing the excisting array ?
last . possibility to print out the new array with the random numbers and index numbers as well ?
best regards
chipollini
View Answers
October 16, 2010 at 2:54 PM
Hi Friend,
Try the following code:
import java.util.*;
class ArrayExample1
{
public static int[] copyArray(int[]... arr) {
int arrSize = 0;
for (int[] array : arr) {
arrSize += array.length;
}
int[] result = new int[arrSize];
int j = 0;
for (int[] array : arr) {
for (int s : array) {
result[j++] = s;
}
}
return result;
}
public static void main(String[] args)
{
Random r=new Random();
int arr[]=new int[5];
System.out.println("Original Array is:");
for(int i=0;i<arr.length;i++){
arr[i]=r.nextInt(10);
System.out.println(arr[i]);
}
System.out.println();
System.out.println("Copied Array is:");
int array[] = (int[]) copyArray(arr);
for(int i=0;i<array.length;i++){
System.out.println(array[i]+" is at index: "+i);
}
}
}
Thanks
Try the following code:
import java.util.*;
class ArrayExample1
{
public static int[] copyArray(int[]... arr) {
int arrSize = 0;
for (int[] array : arr) {
arrSize += array.length;
}
int[] result = new int[arrSize];
int j = 0;
for (int[] array : arr) {
for (int s : array) {
result[j++] = s;
}
}
return result;
}
public static void main(String[] args)
{
Random r=new Random();
int arr[]=new int[5];
System.out.println("Original Array is:");
for(int i=0;i<arr.length;i++){
arr[i]=r.nextInt(10);
System.out.println(arr[i]);
}
System.out.println();
System.out.println("Copied Array is:");
int array[] = (int[]) copyArray(arr);
for(int i=0;i<array.length;i++){
System.out.println(array[i]+" is at index: "+i);
}
}
}
Thanks
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