Create a program called Date.java to perform error-checking on the initial values for instance: fields month, day and year. Also, provide a method nextDay() to increment the day by one. The Date object should always remain in a consistent state. Write a program that tests the nextDay method in a loop that prints the date during each iteration of the loop to illustrate that the nextDay method works correctly. Test the following cases:
a) incrementing into the next month.
// Set Methods.
// Time3 constructor: day, month and year supplied.
}
July 23, 2010 at 12:01 PM
Hi Friend,
Try the following code:
public class Date {
private final int month;
private final int day;
private final int year;
public Date(int m, int d, int y) {
if (!increment(m, d, y))
throw new RuntimeException("Invalid");
month = m;
day = d;
year = y;
}
private static boolean increment(int m, int d, int y) {
int[] DAYS = { 0, 31, 29, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31 };
if (m < 1 || m > 12)
return false;
if (d < 1 || d > DAYS[m])
return false;
if (m == 2 && d == 29 && !isLeapYear(y))
return false;
return true;
}
private static boolean isLeapYear(int y) {
if (y % 400 == 0)
return true;
if (y % 100 == 0)
return false;
return (y % 4 == 0);
}
public Date next() {
if (increment(month, day + 1, year))
return new Date(month, day + 1, year);
else if (increment(month + 1, 1, year))
return new Date(month + 1, 1, year);
else
return new Date(1, 1, year + 1);
}
public String toString() {
return day + "-" + month + "-" + year;
}
public static void main(String[] args) {
Date today = new Date(9, 30, 2010);
System.out.println(today);
for (int i = 0; i < 35; i++) {
today = today.next();
System.out.println(today);
}
}
}
Thanks
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