error:Parameter index out of range (1 > number of parameters, which is 0).

my code:String org=request.getParameter("Org"); String desg=request.getParameter("des"); String From=request.getParameter("From"); String To=request.getParameter("To"); String expdetail=request.getParameter("expdetail"); System.out.println(org); String sqlOption1="Insert into experience(candidateid,org,desg,from,to,expdetail) select * from candidate where candidateid in(select max(candidateid) from candidate)"; String sqlOption2="select candidateid from candidate"; ps1=conn.prepareStatement(sqlOption1); rs=ps1.executeQuery(sqlOption2); System.out.println(ps1); while(rs.next()) { c=rs.getString("candidateid"); } System.out.println(c); ps1.setString(1,c); ps1.setString(2,org); ps1.setString(3,desg); ps1.setString(4,From); ps1.setString(5,To); ps1.setString(6,expdetail); int x=ps1.executeUpdate();

March 7, 2013 at 4:03 PM

hi friend,

You are using PreparedStatement to insert the value. And you are trying to set the value of field using the setXXXX() method of PreparedStatement and in your SQL string you didn't use the ? (question mark) to assign a value. So edit your sql string as follows:

Edit your sql string as INSERT INTO table_name VALUES (?,?,?,?). Number of question mark should be equal to the number of fields in table.

Thanks.

March 7, 2013 at 4:18 PM

you are missing a matching escape

Insert into experience(candidateid,org,desg,from,to,expdetail) select * from candidate where candidateid in(select max(candidateid) from candidate)";

It should be like this

Insert into experience('candidateid', 'org', 'desg', 'from', 'to','expdetail') select * from candidate where candidateid in(select max('candidateid') from candidate)";