Help me

HI I am using Tomcat6.0 this is the problem i got wen i run the code , i am using login.html ,login .jsp,login.java and web.xml code

java.lang.NullPointerException 
org.apache.jsp.loginjsp.jspInit(login_jsp.java:23) 
org.apache.jasper.runtime.HttpJspBase.init(HttpJspBase.java:52) 
org.apache.jasper.servlet.JspServletWrapper.getServlet(JspServletWrapper.java:159) 
org.apache.jasper.servlet.JspServletWrapper.service(JspServletWrapper.java:329) 
org.apache.jasper.servlet.JspServlet.serviceJspFile(JspServlet.java:342) 
org.apache.jasper.servlet.JspServlet.service(JspServlet.java:267) 
javax.servlet.http.HttpServlet.service(HttpServlet.java:717)

// here is code login.jsp

&lt;html&gt;
&lt;body bgcolor=&quot;white&quot;&gt;
&lt;h1&gt; I have been invoked by &amp;lt;%
out.print(request.getAttribute(&amp;quot;servletName&amp;quot;).toString()); %&amp;gt;&lt;/p&gt;
&lt;p&gt;&lt;/body&gt;
&lt;/html&gt;&lt;/p&gt;
&lt;p&gt;login.java&lt;/p&gt;
&lt;p&gt;import java.io.IOException; import java.io.PrintWriter;&lt;/p&gt;
&lt;p&gt;import javax.servlet.RequestDispatcher; import
javax.servlet.ServletException; import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;&lt;/p&gt;

&lt;p&gt;public class Login1 extends javax.servlet.http.HttpServlet implements
javax.servlet.Servlet { static final long serialVersionUID = 1L;&lt;/p&gt;
&lt;p&gt;protected void doGet(HttpServletRequest request, HttpServletResponse
response) throws ServletException, IOException { try{ 
response.setContentType(&amp;quot;text/html&amp;quot;); PrintWriter out=response.getWriter();
String name=request.getParameter(&amp;quot;name&amp;quot;); String 
pass=request.getParameter(&amp;quot;password&amp;quot;);&lt;/p&gt;

if(name.equalsIgnoreCase(&quot;Snipe&quot;)&amp;&amp; pass.equals(&quot;snipe&quot;)){
        // getServletContext().getRequestDispatcher(&quot;/login.jsp&quot;).forward(request,response);
         response.sendRedirect(&quot;/Simple/jsp/login.jsp&quot;);
    }else{
        out.println(&quot;&lt;html&gt;&quot;);
        out.println(&quot;&lt;body&gt;&quot;);
        out.println(&quot;Invalid User name OR passowrds&quot;);
        out.println(&quot;&lt;/body&gt;&quot;);
        out.println(&quot;&lt;/html&gt;&quot;); 
    }

}catch (Exception e) {
e.printStackTrace();
}


} }

// html file is:

&lt;!DOCTYPE html PUBLIC &quot;-//W3C//DTD HTML 4.01 Transitional//EN&quot; 
&quot;http://www.w3.org/TR/html4/loose.dtd&quot;&gt;
&lt;html&gt;
&lt;head&gt;
&lt;meta http-equiv=&quot;Content-Type&quot; content=&quot;text/html; charset=ISO-8859-1&quot;&gt;
&lt;title&gt;User Login&lt;/title&gt;
&lt;/head&gt;
&lt;body bgcolor=&quot;cream&quot;&gt;
&lt;form action=&quot;login&quot; method=&quot;get&quot;&gt;
Enter User name:
&lt;input type=&quot;text&quot; name=&quot;name&quot;&gt;&lt;br&gt;&lt;/p&gt;
&lt;p&gt;Enter Password:
&lt;input type=&quot;password&quot; name=&quot;password&quot;&gt;&lt;br&gt;&lt;/p&gt;
&lt;p&gt;&lt;input type=&quot;submit&quot; name=&quot;submit&quot; value=&quot;login&quot;&gt;&lt;/p&gt;
&lt;p&gt;&lt;/body&gt;
&lt;/html&gt;

and web.xml code:
<?xml version="1.0" encoding="UTF-8"?>
<web-app xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns="http://java.sun.com/xml/ns/javaee" xmlns:web="http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd" xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd" id="WebApp_ID" version="2.5">
  <display-name>ActivityManagementSystem</display-name>

<display-name>Activity Management System</display-name>
  <description>
     Welcome to Web Appllication
  </description> 
    <welcome-file-list>
    <welcome-file>html/Login.html</welcome-file>
    </welcome-file-list>

  <servlet>
    <servlet-name>ZmgrVal</servlet-name>
    <servlet-class>servletapplication.Login1</servlet-class>
  </servlet>

  <servlet-mapping>
    <servlet-name>ZmgrVal</servlet-name>
    <url-pattern>/login</url-pattern>
  </servlet-mapping> 

</web-app>

Does anyone have a clear resolution to this vexing issue? Thanks in advance.

View Answers

December 22, 2010 at 5:12 PM

Hello Friend,

Try this:

1)form.html:

<html>
<form method="post" action="http://localhost:8080/examples/jsp/login.jsp">
<table>
<tr><td>Name:</td><td><input type="text" name="name"></td></tr>
<tr><td>Address:</td><td><input type="password" name="password"></td></tr>
<tr><td></td><td><input type="submit" value="Submit"></td></tr>
</table>
</form>
</html>

2)login.jsp:

<%
   String name = request.getParameter( "name" );
    String pass = request.getParameter( "password" );
   request.setAttribute( "theName", name );
   request.setAttribute( "thePass", pass );
%>

<jsp:forward page="../Login1"/>

3)Login1.java:

import java.io.IOException;
import java.io.PrintWriter;

import javax.servlet.*;
import javax.servlet.http.*;


public class Login1 extends javax.servlet.http.HttpServlet implements javax.servlet.Servlet { static final long serialVersionUID = 1L;

protected void doPost(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException {
    try{
        response.setContentType("text/html");
        PrintWriter out=response.getWriter();
        String name=(String)request.getAttribute("theName");
        String pass=(String)request.getAttribute("thePass") ;
        System.out.println(name+" "+pass);
        if(name.equalsIgnoreCase("Snipe")&& pass.equals("snipe")){
             response.sendRedirect("/examples/jsp/form.html");
        }else{
            out.println("<html>");
            out.println("<body>");
            out.println("Invalid User name OR passwords");
            out.println("</body>");
            out.println("</html>"); 
        }
    }catch (Exception e) {
    e.printStackTrace();
    }
}
}

4)web.xml:

Put the following inside web-app tag:

<servlet>
        <servlet-name>Login1</servlet-name>
        <servlet-class>Login1</servlet-class>
    </servlet>

    <servlet-mapping>
        <servlet-name>Login1</servlet-name>
        <url-pattern>/Login1</url-pattern>
    </servlet-mapping>

Thanks

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