Hi.... if the XML file is small and repetitive then this will have meaning.. import javax.xml.parsers.; import org.xml.sax.; import org.xml.sax.helpers.; import java.io.;

public class SAXElementCount{  
  int startTag = 0;
  public static String ele;
  public static void main(String args[])throws IOException {
  BufferedReader bf = new BufferedReader(new InputStreamReader(System.in));
  System.out.print("Enter XML file name:");
  String xmlFile = bf.readLine();
  File file = new File(xmlFile);
  if (file.exists()){
  System.out.print("Enter XML tag name:");
  ele = bf.readLine();
  SAXElementCount tagCount = new SAXElementCount(xmlFile);
  }
  else{
  System.out.println("File not found!");
  }
  }
  public SAXElementCount(String str){
  try{
  SAXParserFactory parserFact = SAXParserFactory.newInstance();
  SAXParser parser = parserFact.newSAXParser();
  DefaultHandler dHandler = new DefaultHandler(){
  public void startElement(String uri, String name, String element, 
    Attributes atri)throws SAXException{
  if (element.equals(ele)){
  startTag++;
  }
  }
  public void endDocument(){
  System.out.println("Total elements: " + startTag);
  }
  };
  parser.parse(str,dHandler);
  }
  catch (Exception e){
  e.printStackTrace();
  }
  }
}

..

What if the xml file is very big or huge file? and sometimes we wont be aware of type of xml file...