mukut srk fan
Square pattern in java using for loop
1 Answer(s)      4 years and 4 months ago
Posted in : Java Beginners

please explain the logic to program the following using for loop in Java:

1 3 5 7 9

3 5 7 9 1

5 7 8 1 3

7 9 1 3 5

9 1 3 5 7

November 26, 2012 at 12:10 PM

Here is a code that displays the following pattern:

```1 3 5 7 9

3 5 7 9 1

5 7 8 1 3

7 9 1 3 5

9 1 3 5 7

public class Pattern {
public static void main(String[] args) {
int[] array = {1,3,5,7,9};
System.out.println("Original array is:");
printArray(array);
for(int i=1;i<=4;i++){
shift(array, 1);
printArray(array);
}
}

public static void shift(int[] array, int amount) {
for (int j = 0; j < amount; j++) {
int a = array[0];
int i;
for (i = 0; i < array.length - 1; i++)
array[i] = array[i + 1];
array[i] = a;
}
}

public static void printArray(int[] array) {
for (int x = 0; x < array.length; x++) {
System.out.print(array[x] + " ");
}
System.out.println();
}

}
```

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