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MeeraDas
To find first two maximum numbers in an array
2 Answer(s)      5 years and 3 months ago
Posted in : Java Beginners

Java program to find first two maximum numbers in an array,using single loop without sorting array.

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December 27, 2011 at 12:11 PM


import java.util.*;

class ArrayExample {
    public static void main(String[] args) {
        int secondlargest = 0;
        int largest = 0;
        Scanner input = new Scanner(System.in);
        System.out.println("Enter array values: ");
        int arr[] = new int[5];
        for (int i = 0; i < arr.length; i++) {
            arr[i] = input.nextInt();
            if (largest < arr[i]) {
                secondlargest = largest;
                largest = arr[i];
            }
            if (secondlargest < arr[i] && largest != arr[i])
                secondlargest = arr[i];
        }
        System.out.println("Largest number is: " + largest);
        System.out.println("Second Largest number is: " + secondlargest);
    }
}


September 10, 2012 at 2:36 PM


package com.java.interview.array;

import java.util.Scanner;

public class TwoLargestElementsOfArray {

/**
 * @param args
 */
public static void main(String[] args) {
    // TODO Auto-generated method stub
    int secondlargest = 0;
    int largest = 0;
    int size = 0;
    Scanner input = new Scanner(System.in);
    System.out.println("Enter the size of array: ");
    size = input.nextInt();
    int arr[] = new int[size];
    if (size < 2)
        System.out.println("Please enter the valid size of array");
    System.out.println("Enter array values: ");
    for (int i = 0; i < arr.length; i++) {
        arr[i] = input.nextInt();
        if (largest < arr[i]) {
            secondlargest = largest;
            largest = arr[i];
        }
        if (secondlargest < arr[i] && largest != arr[i])
            secondlargest = arr[i];
    }
    System.out.println("Largest number is: " + largest);
    System.out.println("Second Largest number is: " + secondlargest);

}

}










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