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please explain this prog
static void main(String ar[]) throws IOException { BufferedReader br = new BufferedReader(new InputStreamReader(; System.out.println("how many...(String ar[]) throws IOException { BufferedReader br = new
Java read latest file
have got the file name that was at the last. Then using the BufferedReader class... = file.getPath(); BufferedReader reader = new BufferedReader(new FileReader(filename
Java Concatenate files
to the FileReader and BufferedReader which reads the files one by one and store the data...++) { System.out.println("Processing " + files[i].getPath() + "... "); BufferedReader br = new BufferedReader(new FileReader(files[i] .getPath())); String line
XML- read Text Mode - Java Error in Windows - reg. - Java Beginners
creating the code as read the XML file in BufferedReader method. Here I pasted... and output stream FileInputStream fis = new FileInputStream(fin); BufferedReader in = new BufferedReader(new InputStreamReader(fis)); FileOutputStream fos = new
Java Coding - Java Beginners
); BufferedReader bufReader = new BufferedReader(isr); System.out.println("Enter the UPS... InputStreamReader(; BufferedReader bufReader = new BufferedReader(isr... { InputStreamReader isr = new InputStreamReader(; BufferedReader bufReader = new
Java file line reader
. When loop reaches the third line, the br.readLine() method of BufferedReader... { FileReader fr = new FileReader("C:/file.txt"); BufferedReader br = new BufferedReader(fr); for (lineNo = 1; lineNo < 10; lineNo
Java convert string to InputStream
used the BufferedReader class to read and display the converted InputStream. Here... ByteArrayInputStream(text.getBytes("UTF-8")); BufferedReader br = new BufferedReader(new
different type input in java
); } }   Java read input through BufferedReader import*; public class... Exception { BufferedReader reader = new BufferedReader(new
tokenizing a java file
(""); new BufferedReader(new InputStreamReader(fstream)); BufferedReader br = new BufferedReader(new InputStreamReader(fstream)); String strLine
Java Program
(That is an order from my teacher). :-( *BufferedReader should also be used... void main(String[]args)throws Exception{ BufferedReader br=new BufferedReader(new InputStreamReader(; System.out.println("Enter Number