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Random Numbers - shuffling
Posted on: July 26, 2006 at 12:00 AM
The random number methods generate numbers with replacement.

Java Notes

Random Numbers - shuffling

A standard approach to shuffling the elements of an array is to write some code as described below. As of Java 2 the java.util.Collections class contains a static shuffle(list) method, which is described at the bottom.

Shuffling: Random numbers without replacement

The random number methods generate numbers with replacement. This means that a particular random number may be generated repeatedly. If you don't want the same numbers to be repeated, put the values (numbers, strings, objects, ...) in an array, then shuffle the array by randomly exchanging the array elements. The example below shows how to produce the values from 0 to 51 in a random order with no repetition.

Example: Shuffling

A common problem is to shuffle (to randomly rearrange) the elements of an array. Here is how to do that.

Random rgen = new Random();  // Random number generator
int[] cards = new int[52];  

//--- Initialize the array to the ints 0-51
for (int i=0; i<cards.length; i++) {
    cards[i] = i;
}

//--- Shuffle by exchanging each element randomly
for (int i=0; i<cards.length; i++) {
    int randomPosition = rgen.nextInt(cards.length);
    int temp = cards[i];
    cards[i] = cards[randomPosition];
    cards[randomPosition] = temp;
}

java.util.Collections.shuffle(...) for objects (not primitives)

Java has extensive classes for handling data structures, the so-called "Collections" classes. These do not work on simple arrays of primitive values as we have above. If your data is already in one of the collections classes, eg, ArrayList, then you can easily use the java.util.Collections.shuffle() method. Arrays of objects can be converted to ArrayLists by using the java.util.Arrays.asList(. . .) method.

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Copyleft 2005 Fred Swartz MIT License
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