Home Discussion Discuss: JavaScript array get elements at random

  • ErrorGuest June 12, 2011 at 9:48 PM

    It will never pick item 0 of the array(Amit). Use var randomnumber=Math.floor(Math.random()*10) instead.

  • Dynamically change text background colorvengat September 14, 2011 at 1:23 PM

    <html> <head> <title>Javascript Change CSS Class of Div tag</title> <style type="text/css"> .redText,.blueText { width: 200px; font-family: Arial; } .redText { color : green } .blueText { color : blue } </style> <script language="javascript" type="text/javascript"> function changeCssClass(objDivID) { var Random= (Math.round((Math.random()*100)+1)); var Random1= (Math.round((Math.random()*100)+1)); var Random2= (Math.round((Math.random()*100)+1)); var y=15; var x='#'+Random2+Random+Random1; document.getElementById(objDivID).style.background =x; } </script> </head> <body> <center> <div id="div1" class="redText"> By default text indside this HTML div tag is red. Javascript function will change the CSS class<br /> of this Div tag and <br /> text color will change to blue dynamically. </div> <br /> <input type="button" value="click here" onclick="changeCssClass('div1')" /> </center> </body> </html>

  • WRONGStudent April 12, 2012 at 9:16 PM

    THAT SENTENCE IS WRONG. "It shows three random elements from the array at three position in the HTML page." Because you can get same elements from the array. There is a big chance to get same number from 0 - 9 .

  • JavaScript array get elements at randomCurtis May 5, 2012 at 11:00 PM

    Hi, You have some useful information on your site. On your code above, I was wondering: var firstRandomNumber = (Math.round((Math.random()*8)+1)) Since 1 is always added to the Math.random()*8 return value, it doesn't seem that you would ever get 0. I used your code with a slight variation. I was thinking something like: var firstRandomNumber = (Math.round(Math.random()*(arrName.length - 1)) might get the full range of the array. Best, Curtis

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