Home Discussion Discuss: Java error incompatible types

  • javajames January 27, 2012 at 1:17 AM

    userName = keyboardIn.nextLine(); my program wont compile due to this piece of code. It comes out as Incompatible type. I'am a first year student doing java programming. I have declare my variable String userName = new String(); Can anyone see the problem from this because I cant

  • Error: Incompatible typesNehru March 5, 2012 at 6:19 PM

    textfield = new TextField("First Name:", "", 40, TextField.ANY); error: incompatible types textfield = new TextField("First Name:", "", 40, TextField.ANY); required: Textfield found: TextField

  • java-error-incompatibletypesrony October 29, 2012 at 5:33 PM

    public void breadthFirstTraversal(Node rootNode){ Queue q = new LinkedList(); q.add(rootNode); rootNode.visited=true; while(!q.isEmpty()){ Node n = (Node)q.poll(); System.out.print(n.data + " "); for(Node adj : n.adjacentNodes{/*incompatible type required: graphsearch.Node found: java.lang.Object*/ if(!adj.visited){ adj.visited=true; q.add(adj); } } } } How to solve?

  • CamilleriDaniel December 6, 2012 at 1:06 AM

    Thx very much it worked Now i can complete my school project

  • Incompatible Type errorMohan August 30, 2013 at 12:09 PM

    try { char ch=""; for(;;) { ch=st.charAt(0); st=st.substring(1,st.length()); st=st+ch; repaint(); Thread.sleep(100); } } OUTPUT:char ch=""; ^ required:char found:String

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