
adding two integer numbers with using bitwise opeators

Hi Friend,
Try the following code:
public class AddNumberUsingBitwiseOperators {
public static void main(String[] args) {
System.out.println("Adding 5 and 6......");
int x=5,y=6;
int xor, and, temp;
and = x & y;
xor = x ^ y;
while(and != 0 )
{
and <<= 1;
temp = xor ^ and;
and &= xor;
xor = temp;
}
System.out.println(xor);
}
}
Thanks

*hi friends , my name is Rajasekhar kadiveti "43857" the above program has one error,so remove that line i.e is*
and &=xor; the above can be written in simple format .
Logic:
int X,Y; int Z=(((X&Y)<<1)^(X^Y)); System.out.println(Z);
OR
class Sum
{
public static viod main(String args[])
{
int X,Y,A,B;
X=3;
y=4;
A=X&Y;
B=X^Y;
A=A<<1;
int Z=A^B;
System.out.println("sum="+Z);
}
}
out put: step by step
X=0000 0011
Y=0000 0100
A=0000 0000 (X&Y)
B=0000 0111 (X^Y)
A=0000 0000 (A<<1)
Z=0000 0111 (A^B)
Z=7.

Eg:
x = 10, y = 20, z = 0; z = ( (x&y) << 1 ) | (x^y);
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