QuestionAsk Questions?
praveena
how to upload a file using jsp. my operating system is linux.
View Answers
March 25, 2010 at 11:17 AM
Hi Friend,
Try the following code:
1)page.jsp:
<%@ page language="java" %>
<HTml>
<HEAD><TITLE>Display file upload form to the user</TITLE></HEAD>
<BODY> <FORM ENCTYPE="multipart/form-data" ACTION=
"upload.jsp" METHOD=POST>
<br><br><br>
<center>
<table border="0" bgcolor=#ccFDDEE>
<tr>
<center>
<td colspan="2" align="center"><B>UPLOAD THE FILE</B><center></td>
</tr>
<tr>
<td colspan="2" align="center"> </td>
</tr>
<tr>
<td><b>Choose the file To Upload:</b></td>
<td><INPUT NAME="file" TYPE="file"></td>
</tr>
<tr>
<td colspan="2" align="center"> </td>
</tr>
<tr>
<td colspan="2" align="center"><input type="submit" value="Send File"> </td>
</tr>
<table>
</center>
</FORM>
</BODY>
</HTML>
2)upload.jsp:
<%@ page import="java.io.*" %>
<%@ page import="java.sql.*" %>
<% String contentType = request.getContentType();
if ((contentType != null) && (contentType.indexOf("multipart/form-data") >= 0)) {
DataInputStream in = new DataInputStream(request.getInputStream());
int formDataLength = request.getContentLength();
byte dataBytes[] = new byte[formDataLength];
int byteRead = 0;
int totalBytesRead = 0;
while (totalBytesRead < formDataLength) {
byteRead = in.read(dataBytes, totalBytesRead,formDataLength);
totalBytesRead += byteRead;
}
String file = new String(dataBytes);
String saveFile = file.substring(file.indexOf("filename=\"") + 10);
saveFile = saveFile.substring(0, saveFile.indexOf("\n"));
saveFile = saveFile.substring(saveFile.lastIndexOf("\\") + 1,saveFile.indexOf("\""));
int lastIndex = contentType.lastIndexOf("=");
String boundary = contentType.substring(lastIndex + 1,contentType.length());
int pos;
pos = file.indexOf("filename=\"");
pos = file.indexOf("\n", pos) + 1;
pos = file.indexOf("\n", pos) + 1;
pos = file.indexOf("\n", pos) + 1;
int boundaryLocation = file.indexOf(boundary, pos) - 4;
int startPos = ((file.substring(0, pos)).getBytes()).length;
int endPos = ((file.substring(0, boundaryLocation)).getBytes()).length;
FileOutputStream fileOut = new FileOutputStream(saveFile);
fileOut.write(dataBytes, startPos, (endPos - startPos));
fileOut.flush();
fileOut.close();
%><Br><table border="2"><tr><td><b>You have successfully upload the file by the name of:</b>
<% out.println(saveFile);%></td></tr></table>
<%
Connection connection = null;
String connectionURL = "jdbc:mysql://localhost:3306/test";;
ResultSet rs = null;
PreparedStatement psmnt = null;
FileInputStream fis;
try {
Class.forName("com.mysql.jdbc.Driver").newInstance();
connection = DriverManager.getConnection(connectionURL, "root", "root");
File f = new File(saveFile);
psmnt = connection.prepareStatement("insert into file(file_data) values(?)");
fis = new FileInputStream(f);
psmnt.setBinaryStream(1, (InputStream)fis, (int)(f.length()));
int s = psmnt.executeUpdate();
if(s>0) {
System.out.println("Uploaded successfully !");
}
else{
System.out.println("unsucessfull to upload file.");
}
}
catch(Exception e){e.printStackTrace();}
}
%>
Thanks
Try the following code:
1)page.jsp:
<%@ page language="java" %>
<HTml>
<HEAD><TITLE>Display file upload form to the user</TITLE></HEAD>
<BODY> <FORM ENCTYPE="multipart/form-data" ACTION=
"upload.jsp" METHOD=POST>
<br><br><br>
<center>
<table border="0" bgcolor=#ccFDDEE>
<tr>
<center>
<td colspan="2" align="center"><B>UPLOAD THE FILE</B><center></td>
</tr>
<tr>
<td colspan="2" align="center"> </td>
</tr>
<tr>
<td><b>Choose the file To Upload:</b></td>
<td><INPUT NAME="file" TYPE="file"></td>
</tr>
<tr>
<td colspan="2" align="center"> </td>
</tr>
<tr>
<td colspan="2" align="center"><input type="submit" value="Send File"> </td>
</tr>
<table>
</center>
</FORM>
</BODY>
</HTML>
2)upload.jsp:
<%@ page import="java.io.*" %>
<%@ page import="java.sql.*" %>
<% String contentType = request.getContentType();
if ((contentType != null) && (contentType.indexOf("multipart/form-data") >= 0)) {
DataInputStream in = new DataInputStream(request.getInputStream());
int formDataLength = request.getContentLength();
byte dataBytes[] = new byte[formDataLength];
int byteRead = 0;
int totalBytesRead = 0;
while (totalBytesRead < formDataLength) {
byteRead = in.read(dataBytes, totalBytesRead,formDataLength);
totalBytesRead += byteRead;
}
String file = new String(dataBytes);
String saveFile = file.substring(file.indexOf("filename=\"") + 10);
saveFile = saveFile.substring(0, saveFile.indexOf("\n"));
saveFile = saveFile.substring(saveFile.lastIndexOf("\\") + 1,saveFile.indexOf("\""));
int lastIndex = contentType.lastIndexOf("=");
String boundary = contentType.substring(lastIndex + 1,contentType.length());
int pos;
pos = file.indexOf("filename=\"");
pos = file.indexOf("\n", pos) + 1;
pos = file.indexOf("\n", pos) + 1;
pos = file.indexOf("\n", pos) + 1;
int boundaryLocation = file.indexOf(boundary, pos) - 4;
int startPos = ((file.substring(0, pos)).getBytes()).length;
int endPos = ((file.substring(0, boundaryLocation)).getBytes()).length;
FileOutputStream fileOut = new FileOutputStream(saveFile);
fileOut.write(dataBytes, startPos, (endPos - startPos));
fileOut.flush();
fileOut.close();
%><Br><table border="2"><tr><td><b>You have successfully upload the file by the name of:</b>
<% out.println(saveFile);%></td></tr></table>
<%
Connection connection = null;
String connectionURL = "jdbc:mysql://localhost:3306/test";;
ResultSet rs = null;
PreparedStatement psmnt = null;
FileInputStream fis;
try {
Class.forName("com.mysql.jdbc.Driver").newInstance();
connection = DriverManager.getConnection(connectionURL, "root", "root");
File f = new File(saveFile);
psmnt = connection.prepareStatement("insert into file(file_data) values(?)");
fis = new FileInputStream(f);
psmnt.setBinaryStream(1, (InputStream)fis, (int)(f.length()));
int s = psmnt.executeUpdate();
if(s>0) {
System.out.println("Uploaded successfully !");
}
else{
System.out.println("unsucessfull to upload file.");
}
}
catch(Exception e){e.printStackTrace();}
}
%>
Thanks
Related Pages:
If you are facing any programming issue, such as compilation errors or not able to find the code you are looking for.
Ask your questions, our development team will try to give answers to your questions.
Tutorial Topics
