# is this programm efficient to find the day of the given date . can it be more normalized ?

rajesh kumar jain
is this programm efficient to find the day of the given date . can it be more normalized ?
0 Answer(s)      4 years and 8 months ago
Posted in : Date-Calendar
#include <stdio.h>

int main(void)
{
int dd,mm,yy,i,leap=0,ordi=0,odd_years,month_days= 0,total ;
char week[7][10] ;
strcpy(week[0], "Sunday") ;
strcpy(week[1], "Monday") ;
strcpy(week[2], "Tuesday") ;
strcpy(week[3], "Wednesday") ;
strcpy(week[4], "Thursday") ;
strcpy(week[5], "Friday") ;
strcpy(week[6], "Saturday") ;
int month[12]={31,28,31,30,31,30,31,30,31,30,31,30};
scanf("%d %d %d",&dd,&mm,&yy);
for(i=yy-1;i>1;i--)
{
if(i%4==0)
{
leap+=2;
}
else

ordi++;

}

printf("%d %d\n",leap , ordi);
odd_years = leap+ordi;
odd_years = odd_years % 7;
printf("%d\n",odd_years);
for(i=0;i<mm-1;i++)
{
month_days = month_days+ month[i];
}
if(yy%4==0)
{
month_days++;
month_days = month_days % 7;

}
if(yy%4 !=0)
{
month_days = month_days % 7;
}

printf("%d\n",month_days);
dd= dd % 7;
printf("%d\n",dd);
total = odd_years+month_days+dd;
total = total %7;
printf("%d\n",total);
printf("the day is %s",week[total]);

return 0;
}